Fe(II) salt + con. HNO3 點解出NO-－百科全書

標題:

Fe(II) salt + con. HNO3 點解出NO?

發問:

Fe(II) salt + con. HNO3 ---> NO + H2O + Fe(III)ion 點解係出NO.. 唔係出NO2 詳細d~ 更新: 照Uncle Michael所說,, con. HNO3 同 KI(aq) react都會出NO啵~ (dilute左) 不過參考書同教科書都只寫KI會出NO2; Fe(II)會出NO 點解呢? 更新 2: 回wkhrickyyyyy： Fe(II) --> Fe(III)係weak reducing agent 不過你提及(利用一個較強氧化數增減的路徑) 我知NO2比NO stable,, 但轉NO個O.N.跌得仲要多 (+5 --> +2) so, 點解weak reducing agent又會令ON跌得多dd既?

最佳解答:

Case I: NO is formed when adding the solution of an iron(II) salt to concentrated nitric acid The solution contains water. When the solution is added to the concentrated HNO3, the concentrated HNO3 is diluted to become moderately concentrated HNO3 or even dilute HNO3. When moderately concentrated HNO3 or dilute HNO3 acts as an oxidizing agent, nitrogen monoxide gas (NO) is formed. Half equations: Fe2+(aq) → Fe3+(aq) + e- 4H+(aq) + NO3-(aq) + 3e- → 2H2O(l) + NO(g) Overall equation: 3Fe2+(aq) + 4H+(aq) + NO3-(aq) → 3Fe3+(aq) + 2H2O(l) + NO(g) ===== Case II: NO2 is formed when adding the solid of an iron(II) salt to concentrated nitric acid When the solid is added to the concentrated HNO3, the solid is dissolved in the water (solvent) of the concentrated HNO3. This does not affect the concentration of the acid, and it is still concentrated HNO3. When concentrated HNO3 acts as an oxidizing agent, nitrogen dioxide gas (NO2) is formed. Half equations: Fe2+(aq) → Fe3+(aq) + e- 2H+(aq) + NO3-(aq) + e- → H2O(l) + NO2(g) Overall equation: Fe2+(aq) + 2H+(aq) + NO3-(aq) → Fe3+(aq) + H2O(l) + NO2(g) =

其他解答:

同理，如果濃硝酸仍然保持那麼濃，但個氧化劑弱左的話(例如鐵II變鐵III，這不是金屬，是一隻普通的還原劑) 係呢條問題的氧化劑是HNO3, 你這句話它變弱, 在什麼時候才會變弱? 你只講了iron(II) ions are oxidized to iron(III), 似乎同前句冇關係