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標題:
A Maths問題
此文章來自奇摩知識+如有不便請留言告知
發問:
It is given that tan x=-9/40 and 3π/2
最佳解答:
sinx/cosx=-9/40, sin^2x+cos^2x=1, so, cosx = 40/41 and sinx = -9/41 as 3π/2
其他解答:
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標題:
A Maths問題
此文章來自奇摩知識+如有不便請留言告知
發問:
It is given that tan x=-9/40 and 3π/2
最佳解答:
sinx/cosx=-9/40, sin^2x+cos^2x=1, so, cosx = 40/41 and sinx = -9/41 as 3π/2
其他解答: